Sample Question #252 (mathematics)

1) What does the curve

*x*^{2}+*y*^{2}= 1 look like?2) What is an equilateral triangle on this curve (i.e., the vertices of the triangle lie on the curve)?

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Sample Question #252 (mathematics)

1) What does the curve *x*^{2} + *y*^{2} = 1 look like?

2) What is an equilateral triangle on this curve (i.e., the vertices of the triangle lie on the curve)?

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Cool~~~ Quant is Quant

1) I haven’t touched math for a long time, but I guess this explains why:the distance between each point on this curve to (0,0) is (x-0)^2+(y-0)^2, and therefore it is all 1. So the curve is a circle centered at (0,0) and with radius 1.

every point on this unit circle can be written as (cos(a), sin(a)). So for any equilateral triangle inscribed in this circle must have vertices (cos(a),sin(a)), (cos(a+2pi/3), sin(a+2pi/3)), (cos(a+4pi/3), sin(a+4pi/3)), where a can be any real number.