Cool~~~ Quant is Quant
1) I haven’t touched math for a long time, but I guess this explains why:the distance between each point on this curve to (0,0) is (x-0)^2+(y-0)^2, and therefore it is all 1. So the curve is a circle centered at (0,0) and with radius 1.
every point on this unit circle can be written as (cos(a), sin(a)). So for any equilateral triangle inscribed in this circle must have vertices (cos(a),sin(a)), (cos(a+2pi/3), sin(a+2pi/3)), (cos(a+4pi/3), sin(a+4pi/3)), where a can be any real number.
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